Singly Linked List
Singly Linked List
It is the simplest type of linked list in which every node contains some data and a pointer to the next node of the same data type.
Implementation
See the code
#include <bits/stdc++.h>
using namespace std;
// Structure of Node
class Node{
public:
int data;
Node* next;
Node(int data){
this ->data = data;
this ->next = NULL;
}
};
Node* constructLL(vector<int>& arr) {
if(arr.size() == 0){
return NULL;
}
Node *Head = new Node(arr[0]);
Node *temp = Head;
for(int i = 1 ; i < arr.size() ; i++){
Node* new_node = new Node(arr[i]);
temp ->next = new_node;
temp = temp ->next;
}
return Head;
}
void printList(Node* head){
Node* temp = head;
while (temp != NULL) {
cout << temp->data << " ";
temp = temp->next;
}
}
int main(){
vector<int> arr = {1,2,3,4,5};
Node *head = constructLL(arr);
printList(head);
cout<<endl;
return 0;
}
Questions
💡 First try with yourself, if you are unable to solve the question then see the solution.
Linked List Insertion
class Solution{
public:
//Function to insert a node at the beginning of the linked list.
Node *insertAtBegining(Node *head, int x) {
Node* new_node = new Node(x);
new_node ->next = head;
return new_node;
}
//Function to insert a node at the end of the linked list.
Node *insertAtEnd(Node *head, int x) {
Node* new_node = new Node(x);
if(head == NULL){
return new_node;
}
Node* temp = head;
Node* last = NULL;
while(temp != NULL){
last = temp;
temp = temp ->next;
}
last ->next = new_node;
return head;
}
};
Deleting a node in LinkedList
Find the length of the linkedlist
Search an element in the linkedlist
Deletion a node of given index
Node* delete_node(Node* head , int index){
if(head == NULL){
return NULL;
}
if(head != NULL){
if(index == 1){
head = head ->next;
return head;
}
}
Node* pre = NULL;
Node* temp = head;
int count = 0;
while(temp != NULL){
count++;
if(count == index){
pre ->next = temp ->next;
free(pre ->next);
}
pre = temp;
temp = temp ->next;
}
return head;
}
Insertion a node of given index
Node* insert_node(Node* head , int num , int idx){
if(head == NULL){
return NULL;
}
if(head != NULL){
if(idx == 1){
Node* temp = new Node(num);
temp ->next = head;
return temp;
}
}
Node* pre = NULL;
Node* temp = head;
int count = 0;
while(temp != NULL){
count++;
if(count == idx){
Node* new_ele = new Node(num);
pre ->next = new_ele;
new_ele ->next = temp;
}
pre = temp;
temp = temp ->next;
}
return head;
}
Reverse a Linked List
🥇 🥇 🥇
Other Important Questions List
Important Questions List
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